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X^2-28X+192=0
a = 1; b = -28; c = +192;
Δ = b2-4ac
Δ = -282-4·1·192
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-4}{2*1}=\frac{24}{2} =12 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+4}{2*1}=\frac{32}{2} =16 $
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